Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

A sports car accelerates approximately as shown in the velocity-time graph of Fig. 2-43. (The short flat spots in the curve represent manual shifting of the gears.) Estimate the car’s average acceleration in (a) second gear and (b) fourth gear.

FIGURE 2-43Problem 56. The velocity of a car as a function of time, starting from a dead stop. The flat spots in the curve represent gear shifts.

Short Answer

Expert verified

(a) The car’s average acceleration in the second gear is 2.5ms-2.

(b) The car’s average acceleration in the fourth gear is 0.73ms-2.

Step by step solution

01

Step 1. Average acceleration

When the velocity of an object during its motion changes by unequal amounts in equal time periods, the acceleration of the object is variable. Therefore, there is a need to calculate the average acceleration of the object.

Average acceleration of the object in a given time period is calculated by taking the ratio of the change in velocity to the total time taken, i.e.,

Averageacceleration=TotalchangeinvelocityTotaltimetakena¯=ΔvΔt

You can also calculate the average acceleration of the object using the velocity-time graph. The slope of the straight line formed by joining the two points on the velocity-time graph gives the average acceleration of the object between these points.

02

Step 2. (a) Determination of the average acceleration of the car in the second gear

It can be estimated from the graph that the velocity of the sports car in second gear changes from 13ms-1to 23ms-1when the time changes from 4 s to 8 s.

The slope of the velocity-time graph during this interval gives the average acceleration of the car.

Thus, the average acceleration of the car in the second gear can be calculated as shown below.

a¯=ΔvΔt=23-13ms-18-4s=104ms-2=2.5ms-2

So, the car’s average acceleration in the second gear is 2.5ms-2.

03

Step 3. (b) Determination of the average acceleration of the car in the fourth gear

It can be estimated from the graph that the velocity of the sports car in the fourth gear changes from 36ms-1to 44ms-1when the time changes from 16 s to 27 s. The slope of the velocity-time graph during this interval gives the average acceleration of the car.

Thus, the average acceleration of the car in the fourth gear can be calculated as

shown below.

a¯=ΔvΔt=44-36ms-127-16s=811ms-2=0.73ms-2

So, the car’s average acceleration in the fourth gear is 0.73ms-2.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Sketch the v vs t graph for the object whose displacement as a function of time is given by Fig. 2-44.

Figure 2-44 Problems 57,58 and 59

Consider the street pattern shown in Fig. 2–46. Each inter-section has a traffic signal, and the speed limit is 40 km/h. Suppose you are driving from the west at the speed limit. When you are 10.0 m from the first intersection, all the lights turn green. The lights are green for 13.0 s each. (a) Calculate the time needed to reach the third stoplight. Can you make it through all three lights without stopping? (b) Another car was stopped at the first light when all the lights turned green. It can accelerate at the rate of2.00m/s2to the speed limit. Can the second car make it through all three lights without stopping? By how many seconds would it make it, or not make it?

FIGURE 2-46Problem 65

Pelicans tuck their wings and free-fall straight down while diving for fish. Suppose a pelican starts its dive from a height of 14.0 m and cannot change its path once committed. If it takes a fish 0.20 s to perform an evasive action, at what minimum height must it spot the pelican to escape? Assume that the fish is at the surface of the water.

A ball is dropped from the top of a tall building. At the same instant, a second ball is thrown upward from the ground level. When the two balls pass one another, one on the way up, the other on the way down, compare the magnitudes

of their acceleration:

(a) The acceleration of the dropped ball is greater.

(b) The acceleration of the ball thrown upward is greater.

(c) The acceleration of both balls is the same.

(d) The acceleration changes during the motion, so you cannot predict the exact value when the two balls pass each other.

(e) The accelerations are in opposite directions.

A car traveling at 95 km/h strikes a tree. The front end of the car compresses, and the driver comes to rest after traveling 0.80 m. What was the magnitude of the average acceleration of the driver during the collision? Express the answer in terms of ‘g’s’, where 1.00 g = 9.80 m/s2.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free