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Roger sees water balloons fall past his window. He notices that each balloon strikes the sidewalk 0.83 s after passing his window. Roger’s room is on the third floor, 15 m above the sidewalk. (a) How fast are the balloons traveling when they pass Roger’s window? (b) Assuming the balloons are being released from rest, from what floor are they being released? Each floor of the dorm is 5.0 m high.

Short Answer

Expert verified

The speed of the balloons is v=14.054m/s, and the floor from which they are released is the 4th floor.

Step by step solution

01

Step 1. Calculation of the speed of the balloons

Acceleration is expressed as the quantity that indicates the relationship between the variations in the velocity of a particular object in unit time.

Given data.

Time, .t=0.83s.

Distanceh=15m

The height of each floor isd=5m

The relation from the equation of motion is given by.

h=vt+12gt2

Here, g is the gravitational acceleration, v is the required speed, and t is the time.

On plugging the values in the above relation, you get.

15m=v0.83s+129.81m/s20.83s2v=14.054m/s

Thus, v=14.054m/sis the required speed.

02

Step 2. Calculation of distance

The relation to calculate the number of floors is given by.

v2=u2+2gs

Here, u is the initial velocity of the balloons whose value is zero, and s is the distance traveled by the balloon.

On plugging the values in the above relation, you get.

14.054m/s2=02+29.81m/s2ss=10.06m

03

Step 3. Calculation of the number of floors

The number of floors is calculated as.

N=sdN=10.06m5mN2

The total number of floors can be calculated as.

Nt=2+2Nt=4

Thus, Nt=4is the total number of floors.

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