Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

A shopper pushing a cart through a market follows directions to the earned goods and moves through a displacement 8.00i m down one aside. He then makes a 90.0oturn and moves 3.00 m along the y axis. He then makes another 90.0o turn and moves 4.00 m along the x axis . Every shopper who follows these direction correctly ends up 5.00 m from the starting point.

Short Answer

Expert verified

Impossible because 12.4 > 5.00

Step by step solution

01

Definition of vector

A vector is a quantity that has both a direction and a magnitude, and is used to determine the relative location of two points in space.

02

Step 2:Formula

f vector A = a1i + a2j + a3k and vector B = b1i + b2j + b3k then the displacement of AB = (b1 - a1)i + (b2 - a2)j + (b3 - a3)k

If vector A = x1i + y1j + z1k and vector B = x2i + y2j + z2k then the displacement of

The Pythagorean theorem and the definition of tangent will use for calculation

d=x2-x12+y2-y12+z2-z12

03

Calculation

Each shopper must make a choice whether to turn 90o to the left or right, each time he or she makes a turn. One set of such choices, following the rules of the problem, results in the shopper heading in the positive y direction and then again in the positive x direction.

So, the sum of magnitude is

d=8.00i+3.00j+4.00i=12.00i+3.00jd=12.002+3.002d=12.4m12.4>5.00

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free