Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

The mayor of a city reprimands some city employees because they will not remove the obvious sags from the cables that support the city traffic lights. What explanation can the employees give? How do you think the case will be settled in mediation?

Short Answer

Expert verified

The employees would win the case against the city mayor because physics tells s that cables must always sag in order to support their own weight.

Step by step solution

01

A concept:

Force is the force exerted by a rope, string, cable or similar object on one or more objects. Anything pulled, suspended, supported, or swung from a rope, string, cable, etc. is subject to a tensile force. Like all forces, tension can accelerate objects or cause them to deform.

02

The explanation is given by employees:

Consider a cable between two poles. The cable is in equilibrium, meaning that neither end of the cable is moving faster than the other. Let’s divide the cable into little segments which have a certain mass m. Again, in order for the cable to be in equilibrium, every segment needs to be in equilibrium, and the net force on the segments has to be zero.

As known, gravity is acting on our segment of mass m, so you need another force or forces to balance gravity out.

Since gravity acts vertically downwards in this case, you need a vertical component of the tension in the cable left and right.

If the cable was perfectly horizontal then you wouldn’t have had the forces to balance gravity out.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Question:If a man weighs 900 N on the Earth, what would he weigh on Jupiter, where the free-fall acceleration is 25.9 m/s2?

Question: In Figure P5.101, the incline has mass M and is fastened to the stationary horizontal tabletop. The block of mass m is placed near the bottom of the incline and is released with a quick push that sets it sliding upward. The block stops near the top of the incline as shown in the figure and then slides down again, always without friction. Find the force that the table top exerts on the incline throughout this motion in terms of m, M, gand θ.

Question:. An iron bolt of mass 65.0ghangs from a string 35.7cmlong. The top end of the string is fixed. Without touching it, a magnet attracts the bolt so that it remains stationary, but is displaced horizontally 28.0cmto the right from the previously vertical line of the string. The magnet is located to the right of the bolt and on the same vertical level as the bolt in the final configuration. (a) Draw a free-body diagram of the bolt. (b) Find the tension in the string. (c) Find the magnetic force on the bolt.

Question: Your hands are wet , and the restroom towel dispenser is empty . What to do to get drops of water off your hands ? How does the motion of the drops exemplify one of Newton’s law ?

The third graders are on one side of a schoolyard, and the fourth graders are on the other. They are throwing snowballs at each other. As a result, snowballs of various masses are moving with different velocities, as shown in Figure OQ5.3. Rank the snowballs (a) through (e) according to the magnitude of the total force exerted on each one. Ignore air resistance. If two snowballs rank together, make that fact clear.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free