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Suppose you are driving a classic car. Why should you avoid slamming on your brakes when you want to stop in the shortest possible distance? (Many modern cars have antilock brakes that avoid this problem.)

Short Answer

Expert verified

Slamming on the brakes is the shortest possible distance that may cause skidding.

Step by step solution

01

Static and kinetic friction:

Static friction prevents the box from moving without being pushed and must be overcome by a sufficient opposing force before the box will move. Kinetic friction (also referred to as dynamic friction) is a force that resists the relative motion of surfaces once they are in motion.

02

Slamming on the brakes causes skidding:

Skidding is caused by slamming on the brakes. If you brake slower the tires won’t skid and the force between the road and tires will be static friction rather than kinetic friction.

The maximal static friction force is smaller than the kinetic friction force between the tires and the road.

Antilock brakes work by pumping the brakes to minimize skidding of the tires on the road.

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Most popular questions from this chapter

The driver of a speeding truck slams on the brakes and skids to a stop through a distance d. On another trial, the initial speed of the truck is half as large. What now will be the truck’s skidding distance? (a) 2d(b) 2d (c) d (d) d/2 (e) d/4

Question: If an object is in equilibrium, which of the following statements is not true? (a) The speed of the object remains constant. (b) The acceleration of the object is zero. (c) The net force acting on the object is zero. (d) The object must be at rest. (e) There are at least two forces acting on the object.

Question: A block of mass 2.20 kg is accelerated across a rough surface by a light cord passing over a small pulley as shown in Figure P5.99. The tension T in the cord is maintained at 10.0 N, and the pulley is 0.100 m above the top of the block. The coefficient of kinetic friction is 0.400. (a) Determine the acceleration of the block when x = 0.400 m. (b) Describe the general behavior of the acceleration as the block slides from a location where x is large to x= 0 . (c) Find the maximum value of the acceleration and the position x for which it occurs. (d) Find the value of x for which the acceleration is zero.

In Figure OQ5.2, a locomotive has broken through the wall of a train station. During the collision, what can be said about the force exerted by the locomotive on the wall? (a) The force exerted by the locomotive on the wall was larger than the force the wall could exert on the locomotive. (b) The force exerted by the locomotive on the wall was the same in magnitude as the force exerted by the wall on the locomotive. (c) The force exerted by the locomotive on the wall was less than the force exerted by the wall on the locomotive. (d) The wall cannot be said to “exert” a force; after all, it broke.

As shown in figure CQ5.22, student A, a 55 kg girl, sits on one chair with metal runners, at rest on a classroom floor. Student B, an 80 kgboy, sits on an identical chair. Both students keep their feet off the floor. A rope runs from student A’s hands around a light pulley and then over her shoulder to the hands of a teacher standing on the floor behind her. The low-friction axle of the pulley is attached to a second rope held by student B, all ropes run parallel to the chair runners.

  1. If student A pulls on her end of the rope, will her chair or will B’s chair slide on the floor? Explain why?
  2. If instead, the teacher pulls on his rope end, which chair slides? Why this one?
  3. If student B pulls on his rope, which chair slides? Why?
  4. Now the teacher ties his end of the rope to student A’s chair. Student A pulls on the end of the rope in her hands. Which chair slides and why?
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