Question

Figure P12.17 shows a claw hammer being used to pull a nail out of a horizontal board. The mass of the hammer is $\mathbf{1}\mathbf{.}\mathbf{00}\mathit{k}\mathit{g}$.A force of $\mathbf{150}\mathit{N}$is exerted horizontally as shown, and the nail does not yet move relative to the board. Find (a) the force exerted by the hammer claws on the nail

Short answer

(a) The force exerted by the hammer claws on the nail will be$1.04\text{kN at 60}°$ upward and to the right.

Step-by-step solution

Given Information 

Mass of the hammer$M=1.00Kg$

Force exerted horizontally =$\text{150N}$

Force

Force is physical influence on any material or object that can change the magnitude and direction of the motion of any object. It can be mainly denoted by F.

(a) The force exerted by the hammer claws on the nail 

By the given figure if we will take the single point of contact as P then the exerted force by nail on the hammer claws will be R. The mass of hammer is given that is M = 1.00Kg and the normal force that will be exerted on the hammer at point P be n and the friction acting on it is f.

Then by the moments P,

$$\begin{gathered} \left(R\sin 30°\right)0+\left(R\sin 30°\right)\left(5.00\text{cm}\right)+Mg\left(0\right)-\left(\text{150N}\right)\left(30.0\text{cm}\right)=0 \\ R=1039.2N \\ R=1.04\text{kN} \end{gathered}$$

The Force exerted by the hammer on the nail is equal opposite in direction but equal in the magnitude, so it will be $1.04\text{kN at 60}°$upward and to the right.