Question

$$\begin{gathered} \mathit{A}\mathit{n}\mathbf{}\mathit{e}\mathit{l}\mathit{e}\mathit{c}\mathit{t}\mathit{r}\mathit{o}\mathit{n}\mathbf{}\mathit{i}\mathit{n}\mathbf{}\mathit{a}\mathbf{}\mathit{c}\mathit{a}\mathit{t}\mathit{h}\mathit{o}\mathit{d}\mathit{e}\mathbf{-}\mathit{r}\mathit{a}\mathit{y}\mathbf{}\mathit{t}\mathit{u}\mathit{b}\mathit{e}\mathbf{}\mathit{a}\mathit{c}\mathit{c}\mathit{e}\mathit{l}\mathit{e}\mathit{r}\mathit{a}\mathit{t}\mathit{e}\mathit{s}\mathbf{}\mathit{u}\mathit{n}\mathit{i}\mathit{f}\mathit{o}\mathit{r}\mathit{m}\mathit{l}\mathit{y}\mathbf{}\mathit{f}\mathit{r}\mathit{o}\mathit{m}\mathbf{}\mathbf{2}\mathbf{\times }{\mathbf{10}}^{\mathbf{4}}\mathbf{}\mathit{m}\mathbf{/}\mathit{s}\mathbf{}\mathit{t}\mathit{o}\mathbf{}\mathbf{6}\mathbf{\times }{\mathbf{10}}^{\mathbf{6}}\mathbf{}\mathit{m}\mathbf{/}\mathit{s}\mathbf{}\mathit{o}\mathit{v}\mathit{e}\mathit{r}\mathbf{}\mathbf{1}\mathbf{.}\mathbf{50}\mathbf{}\mathit{c}\mathit{m}\mathbf{.}\mathbf{}\mathbf{\left(}\mathit{a}\mathbf{\right)}\mathbf{}\mathit{I}\mathit{n}\mathbf{}\mathit{w}\mathit{h}\mathit{a}\mathit{t}\mathbf{}\mathit{t}\mathit{i}\mathit{m}\mathit{e}\mathbf{}\mathit{i}\mathit{n}\mathit{t}\mathit{e}\mathit{r}\mathit{v}\mathit{a}\mathit{l}\mathbf{}\mathit{d}\mathit{o}\mathit{e}\mathit{s}\mathbf{}\mathit{t}\mathit{h}\mathit{e} \\ \mathbf{}\mathit{e}\mathit{l}\mathit{e}\mathit{c}\mathit{t}\mathit{r}\mathit{o}\mathit{n}\mathbf{}\mathit{t}\mathit{r}\mathit{a}\mathit{v}\mathit{e}\mathit{l}\mathbf{}\mathit{t}\mathit{h}\mathit{i}\mathit{s}\mathbf{}\mathbf{1}\mathbf{.}\mathbf{50}\mathbf{}\mathit{c}\mathit{m}\mathbf{?}\mathbf{}\mathbf{\left(}\mathit{b}\mathbf{\right)}\mathbf{}\mathit{W}\mathit{h}\mathit{a}\mathit{t}\mathbf{}\mathit{i}\mathit{s}\mathbf{}\mathit{i}\mathit{t}\mathit{s}\mathbf{}\mathit{a}\mathit{c}\mathit{c}\mathit{e}\mathit{l}\mathit{e}\mathit{r}\mathit{a}\mathit{t}\mathit{i}\mathit{o}\mathit{n}\mathbf{?} \end{gathered}$$

Short answer

$$\begin{gathered} a)Theintervaloftimeelectrontravel\mathbf{1}\mathbf{.}\mathbf{50}cmis4.98\times {10}^{-9}\mathit{s}. \\ b)Theaccelerationis1.2\times {10}^{15}\mathit{m}\mathbf{/}{\mathit{s}}^{\mathbf{2}}. \end{gathered}$$

Step-by-step solution

Definition of acceleration

The rate at which an object's velocity changes with respect to time is called acceleration. Accelerations are measured in terms of vectors.

The interval of time electron travel of cm

$$\begin{gathered} \left(a\right) \\ Tofindthetime,thisequationisused: \\ {x}_f-x_i=\frac{1}{2}\left(v_i+v_f\right)t \\ Solvingfort: \\ t=\frac{2\left(x_f-x_i\right)}{v_i+v_f} \\ =\frac{2\times 1.5\times {10}^{-2}}{2\times {10}^4+6\times {10}^6} \\ =4.98\times {10}^{-9}m/\mathit{s} \end{gathered}$$

The acceleration

$$\begin{gathered} \left(b\right)Tofindtheacceleration,thisequationisused: \\ {v_f}^2={v_i}^2+2a_x(x_f-x_i) \\ Solvingfor{a}_x: \\ {a}_x=\frac{{v_f}^2-{v_i}^2}{2(x_f-x_i)} \\ =\frac{{\left(6\times {10}^6\right)}^2-{\left(2\times {10}^4\right)}^2}{2\left(1.5\times {10}^{-2}\right)} \\ =1.2\times {10}^{15}\mathit{m}\mathbf{/}{\mathit{s}}^2 \end{gathered}$$