Question

Figure OQ4.1 shows a bird's-eye view of a car going around a highway curve. As the car moves from point 1 to point 2 , its speed doubles. Which of the vectors (a) through (e) shows the direction of the car's average acceleration between these two points?.

Short answer

Correct option is e

Step-by-step solution

Step 1: Define the vector

If a quantity needs both the magnitude and direction for explanation, it is known as vector quantity. The unit vector is a vector with unit magnitude. They only represent directions. It is represented by a lowercase alphabet with a "cap" circumflex. It is denoted as $\hat{\mathrm{u}}$.

Define The average acceleration to vector V1 and V2.

In terms of vector notation, the average acceleration of a particle throughout the time span$\Delta t$ is as follows:

${\overrightarrow{\text{a}}}_{\text{avg}}=\frac{{\overrightarrow{\text{v}}}_{\text{f}}-{\overrightarrow{\text{v}}}_{\text{i}}}{\Delta t}$

Here,${\overrightarrow{v}}_f$ is the final velocity and ${\overrightarrow{v}}_i$is the initial velocity.

As the car is moving on a circular path between points (1) and (2), the average acceleration should be towards the center of circularpath. Therefore, the correct option should be e.

So, the best solution is (e).