Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Show that the kinetic energy of an object rotating about a fixed axis with angular momentum L=Iw can be written asK=L22I .

Short Answer

Expert verified

It is proved that the kinetic energy of an object rotating about a fixed axis with angular momentum L=Iω can be written as K=L22I.

Step by step solution

01

Step 1:

The angular momentum is the amount of rotation of the body, which is the product of its inertia time and angular velocity.

02

Step 2:

Angular momentum

L=Iω

Here, I is the moment of inertia and ω is the angular velocity.

As rotational kinetic energy of an object is,

K=12Iω2=12(Iω)2I=L22I

03

Result

Hence, it is proved that the kinetic energy of an object rotating about a fixed axis with angular momentum L=Iω can be written as K=L22I .

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A disk with moment of inertia I1 rotates about a frictionless, vertical axle with angular speedω. A second disk, this one having moment of inertia I2 and initially not rotating, drops onto the first disk (Fig. ). Because of friction between the surfaces, the two eventually reach the same angular speed ωf.

(a) Calculateωf.

(b) Calculate the ratio of the final to the initial rotational energy.

The displacement vectors 42.0cm at 15.0°and23.0cm at 65.0°both start from the origin and form two sides of a parallelogram. Both angles are measured counter clockwise from the x-axis.

(a) Find the area of the parallelogram.

(b) Find the length of its longer diagonal.

A particle of mass 0.400Kg is attached to the 100cm mark of a meterstick of mass 100Kg . The meterstick rotates on the surface of a frictionless, horizontal table with an angular speed of 4.00rad/s. Calculate the angular momentum of the system when the stick is pivoted about an axis (a) perpendicular to the table through the mark 50.0cm and (b) perpendicular to the table through the 0cm mark.

Question: A wheel 2.00m in diameter lies in a vertical plane and rotates about its central axis with a constant angular acceleration of 4.00rad/s2. The wheel starts at rest at t=0, and the radius vector of a certain point on the rim makes an angle of57.3o with the horizontal at this time. At,t=2.00s find (a) the angular speed of the wheel and, for point P, (b) the tangential speed, (c) the total acceleration, and (d) the angular position.

Question: Three identical thin rods, each of length L and mass m, are welded perpendicular to one another as shown in Figure P10.43. The assembly is rotated about an axis that passes through the end of one rod and is parallel to another. Determine the moment of inertia of this structure about this axis.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free