Question

A rapidly spinning paddle wheel raises the temperature of 200 mL of water from 21°C to 25°C. How much

(a) heat is transferred and

(b) work is done in this process?

Short answer

a. The value of heat is zero

b. The work done energy is 3.4kJ bfvbyfv

Step-by-step solution

Definition of adiabatic process 

This process has ben seen when heat or energy doe not transfer from one system to other. So the amount of heat is zero.

Finding the value of work done energy 

a. Thermal energy for the charges of temperature is $E_{thi}=M_c∆T$

As Q=0J , so $W=E_{thi}=M_c∆T$

b. Now M is material and its equation is $M=\rho V=\left(1g/ml\right)\left(200ml\right)=0.2kg$

Applying all values of M, c, $T_{1,}{T}_2$

The work done is

$$\begin{gathered} =Mc(T_2-T_1)=\left(0.2kg\right)\left(4190J/K.C^o\right){\left(25-21\right)}^{o}C \\ =3.4kJ \end{gathered}$$