Question

How much work is done on the gas in the process shown in Figure EX19.1?

Short answer

The amount of work done energy is$80J$

Step-by-step solution

Definition of work done

The work done has represented as energy that is transferred between system and environment.

Step  2: Finding the work done energy.

In the isobaric process, pressure is negative

Now $W=-p∆V$

$\begin{array}{rcl}V& =& (V_f-V_i)\\ & =& (300-100)m^3\\ & =& 200c{m}^3\end{array}$

Now convert volume cm to m $2\times {10}^{-4}{m}^3$

So the value of work done is

localid="1651380670133" $$\begin{gathered} \mathrm{W}=-\mathrm{p}∆\mathrm{V} \\ =(-400\times {10}^3\times 2\times {10}^{-4}\mathrm{Pa}\times {\mathrm{m}}^3) \\ =-80\mathrm{J} \end{gathered}$$