Question

In Problems 67 through 69 you are given the equation(s) used to solve a problem. For each of these, you are to

a. Write a realistic problem for which this is the correct equation(s).

b. Draw a pictorial representation.

c. Finish the solution of the problem

$$\begin{gathered} F_{push}-(0.20)(30kg)(9.8m/s^2)=0 \\ 75W=F_{push}v \end{gathered}$$

Short answer

a. The mass is $20kg$, the coefficient of kinetic friction isrole="math" localid="1647861976929" $0.15$.

b. The pictorial presentation is as follow:

c. The velocity is $6.3m/s$.

Step-by-step solution

Content Introduction

Mass is a fundamental feature of all matter, and mass is a quantitative measure of it. A force is a push or pull on an object caused by the interaction of the thing with another object.

Explanation (Part a)

The mass is $20kg,$the coefficient of kinetic force isrole="math" localid="1647861968818" $0.15.$

Explanation (Part b)

The pictorial presentation is as follow:

Explanation (Part c)

The velocity is calculated as follow:

$$\begin{gathered} \frac{1}{2}\left[\right(20kg){v_1}^2+0\_(0.15\left)\right(20kg\left)\right(9.8m/s^2\left)\cos \left(40°\right)\frac{2.5m}{\sin \left(40°\right)}\right]=0+(20kg)(9.8m/s^2)(2.5m)+0 \\ {v_1}^2=40.2m^2/s^2 \\ {v}_1=6.3m/s \end{gathered}$$