Question

FIGURE is the kinetic-energy graph for a 2.0 kg object moving along the x-axis. Determine the work done on the object during each of the four intervals AB, BC, CD, and DE.

Short answer

Work Done by

AB: $=-4$J

BC: $=0$J

CD:$=2$J

DE:$=2$J

Step-by-step solution

Step 1. Given Information

We have been given kinetic energy versus time graph

2.0 kg object moving along the x-axis.

Step 2. Find the work done

We will use the concept that change in kinetic energy is equal to work done.

$$\begin{gathered} AB \\ ∆K_{AB}=K_{fAB}-K_{iAB} \\ =0-4=-4J \\ BC \\ ∆K_{BC}=K_{fBC}-K_{iBC} \\ =0-0=0J \\ CD \\ ∆K_{CD}={K_f}_{CD}-K_{i_{CD}} \\ =2-0=2J \\ DE \\ ∆K_{DE}=K_{fDE}-K_{i}DE \\ =4-2=2J \end{gathered}$$