Question

FIGURE P33.56 shows the light intensity on a screen behind a single slit. The slit width is $0.20\mathrm{mm}$and the screen is $1.5\mathrm{m}$behind the slit. What is the wavelength (in nm) of the light?

Short answer

The wavelength of the light$667\mathrm{nm}$

Step-by-step solution

Central Fringe

Remember that the complete width of a main fringes with in the single study is given by

$w_c=\frac{2\lambda L}{a}$

In an intellectual result, we are able to resolve parametrically just for the wavelength to search out an answer.

$\lambda =\frac{a{w}_c}{2L}$

Wavelength

In terms of numbers, our wavelength are going to be

$\lambda =\frac{2\times {10}^{-4}m\times 1\times {10}^{-2}cm}{2mm\times 1.5m}$

$=6.\stackrel{}{6}\times {10}^{-7}m$

$=667\mathrm{nm}$