Question

Suppose you toss three coins into the air and let them fall on the floor. Each coin shows either a head or a tail.

a. Make a table in which you list all the possible outcomes of this experiment. Call the coins A, B, and C.

b. What is the probability of getting two heads and one tail?

c. What is the probability of getting at least two heads?

Short answer

Therefore, the probabilities are:

$$\begin{gathered} \text{b)}P=3/8 \\ c)\hspace{0.17em}P=0.5 \end{gathered}$$

Step-by-step solution

Given information

Suppose you toss three coins into the air and let them fall on the floor. Each coin shows either a head or a tail.

Explanation

The table below lists all of the possible outcomes of the experiment.

b) Because there are eight possible outcomes, each one has a probability of occurrence of (1/8). Looking at the table above, we can see that the two heads and one tail event has happened three times (H T H), (THH), and (HH T), indicating that the chance of having two heads and one tail is:

$P=\frac{1}{8}+\frac{1}{8}+\frac{1}{8}=\frac{3}{8}$

Explanation

c)The phrase "at least two heads" implies that we must consider the outcomes of three heads as well as the three outcomes of two heads.

As a result, the probability that you'll obtain at least two heads is:

$P=\frac{1}{8}+\frac{1}{8}+\frac{1}{8}+\frac{1}{8}=\frac{4}{8}=50\%$