Question

Kami is walking through the airport with her two-wheeled

suitcase. The suitcase handle is tilted 40° from vertical, and

Kami pulls parallel to the handle with a force of 120 N. (Force is

measured in newtons, abbreviated N.) What are the horizontal and

vertical components of her applied force?

Short answer

Horizontal Component F_y = F x Sin40$°$= 120 x 0.64 = 76.8 N

Vertical Component F_x = F x Cos40$°$= 120 x 0.77 = 92.4 N

Step-by-step solution

Given Information:F = 120N∅ = 40° (Force Parallel to Handle)

F_x=F x Sin40⁰= 120 x 0.64 = 76.8N

F_y = F x Cos40⁰ = 120 x 0.77 = 92.4N