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shows three ropes tied together in a knot. One of your friends pulls on a rope with 3.0 units of force and another pulls on a second rope with 5.0 units of force. How hard and in what direction must you pull on the third rope to keep the knot from moving?

Short Answer

Expert verified

Fmakes an angle of 83.4°below the negative x-axis.

Step by step solution

01

Step 1. Given infomation

Consider that the knot in the ropes as particle in static equilibrium. The below figure shows the three ropes tied together in a knot.

From the above figure the magnitude of the force F1is 3 units and the magnitude of the forceF2 is 5 units. Let the magnitude of the third vector be F3.

Angle made by F1with the positive x-axis,θ1=0°

Angle made by F2with the positive x-axis, θ2=120°

Angle made by F3with the negative x-axis,θ

02

Step 2. Explanation

Now express the vectors using the unit vectors.

F1=3iandF2=5sin30°i+5cos30°jSince,F1+F2+F3=0

Rearrange the equation in terms of vectorF3

F3=F1+F2F1=(3)cos0°i^+(3)sin0°j^F2=5sin30°i^+5cos30°j^=2.5i^+4.33j^

Therefore, the vector,F3=[3i^2.5i^+4.33j^]=0.5i^4.33j^

Magnitude of the third force,

F3=(0.5)2+(4.33)2=4.36units

Therefore, the required force you must pull on the third rope to keep the knot from moving is 4.36 units

Direction of F3is,

θ=tan14.360.5=83.4°ln3rdquadrant

Hence, makes an angle of 83.4°below the negative x-axis.

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