Question

Sound wave A delivers 2 J of energy in 2 s. Sound wave B delivers 10 J of energy in 5 s. Sound wave C delivers 2 mJ of energy in 1 ms. Rank in order, from largest to smallest, the sound powers P_A, P_B, and P_C of these three sound waves. Explain

Short answer

The highest power is P_Cand P_B and the lowest is P_A.

P_C= P_B > P_A.

Step-by-step solution

Step 1. Write the given information.

For wave A

The energy delivered E = 2J

The time taken is t = 2s

For wave B

The energy delivered E = 10J

The time taken is t = 5s

For wave C

The energy delivered is E = 2mJ

The time taken is t = 1ms

Step 2. To determine the powers of the three sound waves

The power of the sound waves is given by;

$P=\frac{E\left(J\right)}{t\left(s\right)}$

For wave A

Power is given as;

$P_A=\frac{2J}{2s}=1watt$

Similarly, For wave B, the power is given as;

$P_B=\frac{10J}{5s}=2Watt$

For wave C, the power is given by;

$P_C=\frac{2mJ}{1ms}=2Watt$

Therefore, the highest power is P_Cand P_B and the lowest is P_A.