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A cylinder contains gas at a pressure of 2.0atmand a number density of4.2×1025m-3. The rms speed of the atoms is 660m/s. Identify the gas.

Short Answer

Expert verified

The gas isNeon

Step by step solution

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01

Given information and formula used

Given : Gas is at a pressure : 2.0atm

Number density : 4.2×1025m-3

rms speed of the atoms : 660m/s

Theory used :

To identify a gas, we must first determine its molar mass. The mass of one mole, Mor the Avogadro number of molecules . That is, if the mass of a single molecule is m, M=mNAwill result.

Remember that the pressure may be defined in terms of molecular mass, number density, and rms speed as p=13NVmv2rmsto express the mass of one atom.

02

Identifying the gas 

m=3pN/Vv2rmsAs a result, we can write the molecular mass as .

We get role="math" localid="1649059712027" M=mNA=3pNAN/Vv2rmsby plugging this result into the preceding one.

M=3×2×105×6.02×10234.2×1025×6602=0.0197kgwill be the result.

In gram terms, this is 19.7g.

We can find periodic tables in periodic tables. We can find the molar mass of neon in periodic tables at 20.1, thus we can say our gas is Neon within a little margin of error.

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