Question

Points 1 and 2 in FIGURE EX 29.2 are the same distance from the wires as the point where $B=2.0\mathrm{mT}$. What are the strength and direction of$\overrightarrow{B}$ at points 1 and 2 ?

Short answer

The strength and direction of $\overrightarrow{B}$is

$B_1=2\mathrm{mT}\text{into the page and}{B}_2=0\mathrm{mT}\text{.}$

Step-by-step solution

Introduction

Be using the right-hand principle to arrange the finger tips in the direction indicated because the other finger curve around at the string and indicate the magnetic direction to compute the route of the fields.

Magnetic Field

A produces a magnetic field either by wires. For the magnetic attraction at line 1, the bottom line, that would have been conducting a signal towards the left, is charge. As a result, the magnet at position 1 is

$B_1=2\mathrm{mT}$

Right-hand Rule

The fingers curl into the page when we hire the best principle of the bottom wire, and has been the path of the magnetic force at position 1.

The another one is in the Centre of both wires. A generates a magnetic field by the lower line and transmitted into the page. The upper wire's magnetic force is the same amount as the bottom wire's, but its path should be off the page at point 2, giving a total magnetism of zero at point 2.

$B_2=2\mathrm{mT}-2\mathrm{mT}=0\mathrm{mT}$