Question

The polonium isotope${}^{211}\mathrm{Po}$is radioactive and undergoes alpha decay. In the decay process, a ${}^{211}\mathrm{Po}$nucleus at rest explodes into an alpha particle (a ${}^4\mathrm{He}$nucleus) and a ${}^{207}\mathrm{Pb}$lead nucleus. The lead nucleus is found to have $0.14\mathrm{MeV}$ of kinetic energy. The energy released in a nuclear decay is the total kinetic energy of all the decay products. How much energy is released, in MeV, in a${}^{211}\mathrm{Po}$ decay?

Short answer

s

Step-by-step solution

Given information

We have given,

Kinetic energy of Pb =$0.14\mathrm{MeV}$

we have to find the total energy or the total kinetic energy.

Simplify

s