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An alpha particle (a bare helium nucleus with q = +2e) accelerates across a 100 V potential difference, starting from rest. What is the particle’s kinetic energy in eV when it reaches the negative electrode? This question requires no mathematics beyond what you can do in your head.

Short Answer

Expert verified

The particle’s kinetic energy in eV is 200eV

Step by step solution

01

Given information

charge = 2e.

potential difference = 100V

02

Step 2: 

Kinetic Energy = q*potential difference

2e*100=200eV

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