Question

$FIGUREQ25.11$shows three points near two point charges. The charges have equal magnitudes. For each part, rank in order, from most positive to most negative, the potentials $V_a$to $V_c$.

Short answer

Part $\left(a\right)$

$\left(a\right)$From most positive to most negative,the potential is$V_b>V_a=V_c.$

Part $\left(b\right)$

$\left(b\right)$From most positive to most negative,the potential is$V_a>V_b>V_c.$

Step-by-step solution

Step: 1 Three to two point charges from most positive to most negative: (part a)

From potential,

$V=\frac{q}{4\pi {ϵ}_{0}r}$and

symmetry system and also negative charge decrease the potential.

By following above these,

$V_b>V_a=V_c.$

Step: 2 Three to two point charges from most positive to most negative: (part b) 

From potential,

$V=\frac{q}{4\pi {ϵ}_{0}r}$and

symmetrical system and also negative charge deduces the potential.

By following above these,

$V_a>V_b>V_c.$