Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

A parallel-plate capacitor has 2.0cm×2.0cmelectrodes with surface charge densities ±1.0×106C/m2. A proton traveling parallel to the electrodes at 1.0×106m/s enters the center of the gap between them. By what distance has the proton been deflected sideways when it reaches the far edge of the capacitor? Assume the field is uniform inside the capacitor and zero outside the capacitor.

Short Answer

Expert verified

The proton been deflected sideways when it reaches the far edge of the capacitor is

a=0.108×1014m2s

t=2×108sec

y=2.2mm

Step by step solution

01

Acceleration and Velocity

η=1×106( charge densities)

From inside battery, there must be an electric current due to just a paired surface.

E=ηϵo=acceleration

a=qEmp

=qηϵomp

a=1.6×1019×1068.85×1012×1.67×1027

a=0.108×1014m2s

So there is no force as in downward motion, the pace is same:

d=vt

t=dv

=2×102106

=2×108sec

02

Distance

With in vertical motion, ion sweep area

y=ut+12at2

y=12×0.108×1014×2×1082

y=2.2mm

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

What are the strength and direction of the electric field at the position indicated by the dot in FIGURE EX23.1? Specify the direction as an angle above or below horizontal

What are the strength and direction of the electric field at the position indicated by the dot in FIGUREEX23.3?Specify the direction as an angle above or below horizontal.

What are the strength and direction of the electric field at the position indicated by the dot in FIGUREP23.37? Give your answer (a)in component form and (b)as a magnitude and angle measured cwor ccw(specify which) from the positive x-axis.

An electron traveling parallel to a uniform electric field increases its speed from 2.0×107m/sto4.0×107m/s over a distance of 1.2cm. What is the electric field strength?

One type of ink-jet printer, called an electrostatic ink-jet printer, forms the letters by using deflecting electrodes to steer charged ink drops up and down vertically as the ink jet sweeps horizontally across the page. The ink jet forms30μm diameter drops of ink, charges them by spraying 800,000 electrons on the surface, and shoots them toward the page at a speed of 20m/s. Along the way, the drops pass through two horizontal, parallel electrodes that are 6.0mmlong,4.0mm wide, and spaced 1.0mm apart. The distance from the center of the electrodes to the paper is 2.0cm. To form the tallest letters, which have a height of 6.0mm, the drops need to be deflected upward (or downward) by 3.0mm. What electric field strength is needed between the electrodes to achieve this deflection? Ink, which consists of dye particles suspended in alcohol, has a density of 800kg/m3 .

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free