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Two parallel plates1.0cmapart are equally and oppositely charged. An electron is released from rest at the surface of the negative plate and simultaneously a proton is released from rest at the surface of the positive plate. How far from the negative plate is the point at which the electron and proton pass each other?

Short Answer

Expert verified

The negavie plate isd1cm

Step by step solution

01

Step 1:Introduction

Equation gives the force between the panels.:ma=qE

For electron

a1=qEme

For proton

a2=qEmp

If distance dtravel by electron of time twhen meet the proton:

d=ut+12at2

Substitute u=0

d=12a1t2.........(1)

At same time tdistance travel by proton when meet the electron:

(1-d)=12a2t2.......(2)

02

Substitution

From 1and 2, we find next

10-2×1=12a1+a2t2

t2=2×10-2a1+a2

Now, value for t2, substitute in the equation for d.

d=12a1t2

=12·a1×2×10-2a1+a2

=12·2×qEme×10-2qEme+qEmp

=10-2×mpme+mp

=1.67×10-27×10-29.11×10-31+1.67×10-27

=0.991cm

03

value of electron and proton

The electron and proton 1cmpass each other.

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