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A2.0m×4.0mflat carpet acquires a uniformly distributed charge of -10μCafter you and your friends walk across it several times. A2.5μgdust particle is suspended in midair just above the center of the carpet. What is the charge on the dust particle?

Short Answer

Expert verified

The charge on the dust particle is-3.47×10-13C.

Step by step solution

01

Calculation of charge density

Given,

Q=-10×10-6C

g=9.8m/s2

m=0.0025×10-6kg

ϵo=8.85×10-12C2/Nm2

F=mg=qE

η=QA

The charge density by dividing the charge(Q)by the area(2.0×4.0)m,

η=-10×10-6C(2.0m×4.0m)

η=-1×10-58.0m

η=-1.25×10-6C/m2

02

Calculation of Electric field 

To calculate the electric field, multiply the charge density by the temporal permittivity constant.

Electric field,

E=η2ϵo

E=-1.25×10-6C/m22×8.85×10-12C2/Nm2

E=-7.06×104N/C

03

Calculation for charge

To calculate the charge of a dust particle, multiply the mass times gravity by the electrical field.

q=mgE

q=0.0025×10-6×9.8-7.3×104

q=-3.47×10-13C

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Most popular questions from this chapter

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Hint: Can you create this charge distribution as a superposition of charge distributions for which you know the electric field?

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