Question

|| The three identical loudspeakers

in FIGURE P17.71 play a 170 Hz tone

in a room where the speed of sound

is 340 m/s. You are standing 4.0 m

in front of the middle speaker. At

this point, the amplitude of the wave

from each speaker is a.

a. What is the amplitude at this

point?

b. How far must speaker 2 be moved

to the left to produce a maximum

amplitude at the point where you

are standing?

c. When the amplitude is maximum,

by what factor is the sound intensity

greater than the sound intensity from a single speaker?

Short answer

The solutions give a detailed description of three identical loudspeakers and the point of amplitude.

Step-by-step solution

Description of point amplitude

Amplitude in Physics is the displacement and the distance moved by a point

Explanation of the solutions

Provided solutions$$\begin{gathered} ∆\mathrm{\pi }=\sqrt{3^2+4^2}-4=1\mathrm{m} \\ ∆\varnothing =2\mathrm{\pi }\frac{∆\mathrm{r}}{\mathrm{\lambda }}=2\mathrm{f\pi }\frac{∆\mathrm{r}}{\mathrm{v}}=\frac{2.170.1.\mathrm{\pi }}{340}=\mathrm{\pi } \end{gathered}$$