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Two out-of-phase radio antennas at x = ±300 m on the x-axis are emitting 3.0 MHz radio waves. Is the point (x, y) = (300 m, 800 m) a point of maximum constructive interference, maximum destructive interference, or something in between

Short Answer

Expert verified

The constructive interference of second order is formed

Step by step solution

01

Write the given information

The distance between the two antennas d = 600m

The frequency of the signal f= 3.0MHz

The speed of the signal is c (3x108m/s)

The signals are out of phase, thus the phase difference between the signals is π

02

To determine the kind of interference at (x,y)= (300m,800m)

The wavelength of the signal is expressed as

λ=cf=3×108m/sec3×106sec-1λ=100m

Thus, the wavelength of the signal is 100m.

The following diagram shows the given situation

The distance AB = 600m

The point C is (300m, 800m)

Thus, the vertical distance BC= 800m

From Pythagoras theorem, AC is

AC=6002+8002AC=1000m

Thus, the distance of point C from the radio signal A is 1000m

The path difference of the signal at point C is

x=AC-BCx=(1000-800)mx=200m
The path difference is 200m


If the interference is destructive at point C

The condition satisfied by the path difference is given

role="math" localid="1649934716581" x=m+12λ

here, m is an integer. Now, substitute the values in the above relation to determine m

200=m+12100m=2-12=1.5(notpossible)
Since the value of m is always an integer, thus at point C, there is no destructive interference.

If the interference is constructive at point C

The condition satisfied by the path difference is given

x=mλ200=m(100)m=2
Here, the value of m is an integer, therefore, at point C the constructive interference of second order is formed

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