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Vector A=3ı^+ȷ^ and vector B=3ı^-2ȷ^+2k^ . What is the cross product A×B ?

Short Answer

Expert verified

The cross product of the vectors Aand Bis 2i^-6j^-9k^.

Step by step solution

01

Introduction

Use the expression for cross product of two vectors to solve the given problem. Consider two vectors which are in terms of i^,j^and k^as follows.

A=a1i^+a2j^+a3k^

B=b1i^+b2j^+b3k^

02

Step :2 Explanation

The vector product of the two vectors is,

A×B=i^j^k^a1a2a3b1b2b3

A×B=i^    j^    k^a1    a2    a3b1    b2    b3

=a2b3a3b2i^+a3b1a1b3j^+a1b2a2b1k^

03

Step :3 Given vectors 

The cross product of the given vectorsA=3i^+j^and B=3i^-2j^+2k^is expressed as follows.

A×B=(3i^+j^)×(3i^-2j^+2k^)A×B=i^j^k^3103-22=[(1)(2)-(0)(-2)]i^+[(0)(3)-(3)(2)]j^+[(3)(-2)-(1)(3)]k^=2i^-6j^-9k^

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