Question

An object is $20\mathrm{cm}$in front of a converging lens with a focal length of $10\mathrm{cm}$. Use ray tracing to determine the location of the image. Is the image upright or inverted?

Short answer

Therefore from given data the image is inverted

Step-by-step solution

Using Tracing diagram

The following three points are followed according to the ray tracing graphic.

The object's first light ray is made to pass through the lens's centre.

The second light ray is produced to pass via the second focal point of the lens, which is parallel to the principle axis.

The third light ray passes through the lens's first focal point and is refracted parallel to the principal axis by the lens.

The image's position is determined by the junction of the three refracted rays.

Schematic Representation.

Draw the schematic model of the object and its image using ray tracing:

Conclusion

The location of the object in front of the lens is $0$, whereas the position of the image behind the lens is $I$.

Because the item is two times the focal length in front of the lens, its image will be generated at a distance of two times the focal length behind the lens.

As a result, the image will be inverted.