Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

You see an upright, magnified image of your face when you look into a magnifying cosmetic mirror. Where is the image? Is it in front of the mirror's surface, on the mirror's surface, or behind the mirror's surface? Explain.

Short Answer

Expert verified

The magnified image forms behind the surface of the mirror.

Step by step solution

01

definition of mirror

Unlike mirrors, most natural surfaces are rough on the scale of the wavelength of light, and as an outcome, parallel incident light rays are reflected in many different directions irregularly or diffusely.

02

Step 2:Find image

A magnifying cosmetic mirror is a concave mirror with a large radius of curvature and thus a large focal length. It works as follows. When your face is less than one focal length in front of it, a magnified virtual image of your face forms behind the mirror's surface. The figure below depicts a ray diagram of this situation.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The illumination lights in an operating room use a concave mirror to focus an image of a bright lamp onto the surgical site. One such light uses a mirror with a 30 cm radius of curvature. If the mirror is 1.2 m from the patient, how far should the lamp be from the mirror?

Shows a light ray that travels from point A to point B. The ray crosses the boundary at position x, making angles ฮธ1and ฮธ2in the two media. Suppose that you did not know Snellโ€™s law.

A. Write an expression for the time t it takes the light ray to travel from A to B. Your expression should be in terms of the distances a, b, and w; the variable x; and the indices of refraction n1 and n2

B. The time depends on x. Thereโ€™s one value of x for which the light travels from A to B in the shortest possible time. Weโ€™ll call it xmin. Write an expression (but donโ€™t try to solve it!) from which xmincould be found.

C. Now, by using the geometry of the figure, derive Snellโ€™s law from your answer to part b.

Youโ€™ve proven that Snellโ€™s law is equivalent to the statement that โ€œlight traveling between two points follows the path that requires the shortest time.โ€ This interesting way of thinking about refraction is called Fermatโ€™s principle.

An astronaut is exploring an unknown planet when she accidentally drops an oxygen canister into a 1.50-m-deep pool filled with an unknown liquid. Although she dropped the canister 21 cm from the edge, it appears to be 31 cm away when she peers in from the edge. What is the liquidโ€™s index of refraction? Assume that the planetโ€™s atmosphere is similar to earthโ€™s

A light ray leaves point Ain FIGURE EX34.5, reflects from the mirror, and reaches point B. How far below the top edge does the ray strike the mirror?

An object is 30cmin front of a convex mirror with a focal length of -20cm. Use ray tracing to locate the image. Is the image upright or inverted?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free