Question

How many photoelectrons are ejected per second in the experiment represented by the graph of FIGURE EX38.2?

Short answer

There are$6250$photo electrons are ejected per seconds.

Step-by-step solution

Given information

We have given, the graph between the current and the potential.

We have to find the photoelectrons ejected per second.

Simplify

the current is found out from the graph is

$$\begin{gathered} \mathrm{I}=10\mathrm{\mu A} \\ \mathrm{i}={10}^{-5}\mathrm{A} \end{gathered}$$

we know that the charge of one electron is $1.6\times {10}^{-19}\mathrm{C}$.

then the photoelectron per second is ejected is ,

$$\begin{gathered} \mathrm{n}=\frac{\mathrm{I}}{\mathrm{e}} \\ \mathrm{n}=\frac{{10}^{-15}}{1.6\times {10}^{-19}} \\ \mathrm{n}=6250 \end{gathered}$$