Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Estimate the electric fields E1and E2 at points 1 and 2 in Figure Q26.4. Don’t forget thatE is a vector.

Short Answer

Expert verified

The electric field remains constant while the potential increases uniformly.

Step by step solution

01

: Given information and formula used   

Given :

Theory used :

Electric Field is given by : E=Vr

02

Estimating E→1 and E→2

(a) As per the figure,

V = 5 volts, r=0.5m

So, E=50.5=10V/m(direction : Leftwards )

(b) As per the figure,

V = 35 volts, r = 3.5m

So, E=353.5=10V/m(direction : Rightwards )

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Two 10-cm-diameter electrodes 0.50 cm apart form a parallelplate capacitor. The electrodes are attached by metal wires to the terminals of a 15 V battery. What are the charge on each electrode, the electric field strength inside the capacitor, and the potential difference between the electrodes a. While the capacitor is attached to the battery? b. After insulating handles are used to pull the electrodes away from each other until they are 1.0 cm apart? The electrodes remain connected to the battery during this process. c. After the original electrodes (not the modified electrodes of part b) are expanded until they are 20 cm in diameter while remaining connected to the battery?

The parallel-plate capacitor in Figure Q26.11 is connected to a battery having potential difference Vbat. Without breaking any of the connections, insulating handles are used to increase the plate separation to 2d.

a. Does the potential difference VCchange as the separation increases? If so, by what factor? If not, why not?

b. Does the capacitance change? If so, by what factor? If not, why not?

c. Does the capacitor charge Qchange? If so, by what factor? If not, why not?

A nerve cell in its resting state has a membrane potential of -70mV, meaning that the potential inside the cell is 70mV less than the potential outside due to a layer of negative charge on the inner surface of the cell wall and a layer of positive charge on the outer surface. This effectively makes the cell wall a charged capacitor. When the nerve cell fires, sodium ions,Na+, flood through the cell wall to briefly switch the membrane potential to +40mV. Model the central body of a nerve cell-the soma-as a 50μmdiameter sphere with a 7.0-nm-thick cell wall whose dielectric constant is 9.0. Because a cell's diameter is much larger than the wall thickness, it is reasonable to ignore the curvature of the cell and think of it as a parallel-plate capacitor. How many sodium ions enter the cell as it fires?

a. Use the methods of Chapter 25 to find the potential at distance xon the axis of the charged rod shown in FIGURE P26.43.

b. Use the result of part a to find the electric field at distance xon the axis of a rod

Consider a uniformly charged sphere of radius R and total cAlC charge Q. The electric field Eout outside the sphere(rR) is simply that of a point charge Q. In Chapter 24, we used Gauss's law to find that the electric field Ein inside the sphere(rR) is radially outward with field strength

Ein=14πϵ0QR3r

a. The electric potential Voutoutside the sphere is that of a point charge Q. Find an expression for the electric potentialVinat position r inside the sphere. As a reference, let Vin=Voutat the surface of the sphere.

b. What is the ratio Vcenter/Vsurface?

c. Graph V versus r for 0 r 3 R.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free