Question

How much work does the electric motor of a Van de Graaff generator do to lift a positive ion $(q=e)$ if the potential of the spherical electrode is $1.0MV$?

Short answer

Work done is$\mathbf{1}\mathbf{.}\mathbf{60}\mathbf{\times }{\mathbf{10}}^{\mathbf{-}\mathbf{13}}\mathbf{}\mathit{J}$

Step-by-step solution

Given information and theory used

Given :

Charge of positive ion : $q=e$

Potential of the spherical electrode : $1.0MV$

Theory used :

The work is equal to $W=q∆V$

Calculating work done  

Since we have, $W=q∆V$

$$\begin{gathered} \Rightarrow W=1.6·{10}^{-19}C·1.0·{10}^{6}V \\ =\boxed{\mathbf{1}\mathbf{.}\mathbf{60}\mathbf{\times }{\mathbf{10}}^{\mathbf{-}\mathbf{13}}\mathbf{}\mathit{J}} \end{gathered}$$