Question

Figure EX26.12 is a graph of $V\mathrm{versus}x$. Draw the corresponding graph of $E_x\mathrm{versus}x.$

Short answer

We've drawn the required graph with slopes$5000V/m\mathrm{and}-5000V/m$

Step-by-step solution

Given information and theory used  

Given :

Theory used :

The electric field is expressed as a function of potential as :

$E\left(x\right)=-\frac{dV\left(x\right)}{dx}$

Drawing the corresponding graph of Ex versus x. 

The potential graph in our situation consists of two lines. As a result, the derivative will be a constant, namely the line's slope. The slopes can be seen to be steep.

$5000V/m\mathrm{and}-5000V/m$are the slopes when drawing the graph. As a result, our graph would look like this: