Question

Figure EX26.11 is a graph of$V\mathrm{versus}x$. Draw the corresponding graph of$E_x\mathrm{versus}x$.

Short answer

We've drawn the required graph with$E_x=-2000$

Step-by-step solution

Given information and theory used  

Given :

Theory used :

The field component $E$ is equal to minus the slope of the graph of the potential $V$

Calculating Ex

The field component $E$is equal to minus the slope of the graph of the potential $V$

As a result, for$x$between $0\mathrm{and}10cm\mathrm{and}x>20cm$, because $V$does not vary. Between $10\mathrm{and}20cm$, the potential varies in a consistent manner from $-100V\mathrm{to}100V,$assuming a constant field of :

$E_x=-\frac{100V-(-100V)}{0.2m-0.1m}=\boxed{-2000V/m}.$

Formulating table and graph

Table :

Position	Electric Field
$0-10cm$	$0V/m$
$10-20cm$	$-2000V/m$
$20-30cm$	$0V/m$

Graph :