Question

What is the potential difference between $x_i=10cm$ and $x_f=30cm$ in the uniform electric field $E_x=1000V/m$?

Short answer

$\mathbf{-}\mathbf{200}\mathbf{}\mathit{v}\mathit{o}\mathit{l}\mathit{t}\mathit{s}$is the potential difference.

Step-by-step solution

Given information and formula used

Given :

$x_i=10cm$ ; $x_f=30cm$

Uniform electric field : $E_x=1000V/m$

Theory used :

The potential decrease is provided by the formula : $∆V=-E(x_f-x_i)$

Calculating the required the potential difference 

The field is uniform and oriented in the $x$direction.

So, using the formula we get :

role="math" localid="1649493329471" $$\begin{gathered} ∆V=-E(x_f-x_i) \\ \Rightarrow ∆V=\boxed{\mathbf{-}\mathbf{200}\mathbf{}\mathit{V}} \end{gathered}$$