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Your task in physics laboratory is to make a microscope from two lenses. one lens has a focal length of 2.0cm,the other objective, and you want the eyepiece to be 16cmfrom the objective.

(a). For viewing with a relaxed eye, how far should the sample be from the objective lens?

(b). What is the magnification of your microscope?

Short Answer

Expert verified

(a). The sample should be 1.066cmapart from the objective lens.

(b). The magnification of your microscope M200.

Step by step solution

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01

Part(a) Step 1: Given information

We have given that:

The focal length of eye isfe=2.0cm

the focal length of object isfo=1.0cm

and the distance between eyepiece and object is 16cm.

We need to find what is the magnification of your microscope.

02

Part (a) Step 2: Simplification

We use the formula,

1fo=1S+1d

11-116=1S

1516=1S

S=1.066cm.

Here Sis distance of sample from objective lens, f0is the focal length of the object and dis the distance between lens and object.

03

part (b) step 1: Given Information

We need to find the magnification.

04

part (b) step 2: Calculation

For Magnification we can use:

M=dS1+Dfe

M=161.0661+252

M200.

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Most popular questions from this chapter

Modern microscopes are more likely to use a camera than human viewing. This is accomplished by replacing the eyepiece in Figure 35.14 with a photo-ocular that focuses the image of the objective to a real image on the sensor of a digital camera. A typical sensor is 22.5 mm wide and consists of 5625 4.0@mm@ wide pixels. Suppose a microscopist pairs a 40* objective with a 2.5* photo-ocular.

a. What is the field of view? That is, what width on the microscope stage, in mm, fills the sensor?

b. The photo of a cell is 120 pixels in diameter. What is the cell’s actual diameter, in mm?

To focus parallel light rays to the smallest possible spot, should you use a lens with a small f-number or a large f-number? Explain.

The resolution of a digital cameras is limited by two factors diffraction by the lens, a limit of any optical system, and the fact that the sensor is divided into discrete pixels. consirer a typical point-and--shoot camera that has a 20-mm-focal-lengthlens and a sensor with 2.5-μm-widepixels.

(a) . First, assume an ideal, diffractionless lens, at a distance of 100m,what is the smallest distance, in cmbetween two point sources of light that the camera can barely resolve? in answering this question, consider what has to happen on the sensor to show two image points rather than one you can use S1=fbecauses>>f.

(b) . You can achieve the pixel-limied resolution of part a only if the diffraction which of each image point no greater than the diffraction width of image point is no greater than 1pixel in diameter. for what lens diameter is the minimum spot size equal to the width of a pixel ? use 600nmfor the wavelength of light.

(c). what is the f-numberof the lens for the diameter you found in part b? your answer is a quite realistic value of the f-numberat which a camera transitions from being pixel limited to being diffraction limited for f-numbersmaller than this (larger-diameter apertures), the resolution is limited by the pixel size and does not change as you change the apertures. for f-numberlarger than this (smaller-diameter apertures). the resolution is limited by diffraction and it gets worse as you "stop down" to smaller apertures.

A microscope has a 20cmtube length. What focal-length objective will give total magnification localid="1649845070556" 500×when used with an eyepiece having a focal length 5.0cm?

what is the f-numberof a relaxed eye with the pupil fully dilated to localid="1648735653936" 8.0mm? model the eye as a single lens localid="1648735646217" 2.4cmin front of the retina.

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