Question

The cornea, a boundary between the air and the aqueous humor, has a $3.0cm$focal length when acting alone. What is its radius of curvature?

Short answer

The radius of curvature is$R=0.76cm$

Step-by-step solution

Given Information.

We have given that:

The focal length is$3.0cm$.

We need find out the radius of curvature.

Simplify 

By using formula:

$\frac{n_1}{s}+\frac{n_2}{s^{\text{'}}}=\frac{(n_1-n_2)}{R}$

From previous formula, Let us find R:

$$\begin{gathered} \frac{1}{\infty }+\frac{n_2}{f}=\frac{n_2-n_1}{R} \\ R=f\left(\frac{n_2-n_1}{n_2}\right) \\ R=3.0\times \left(\frac{1.34-1.00}{1.34}\right) \\ R=3.0\times \left(\frac{0.34}{1.34}\right) \\ R=3.0\times 0.253 \\ R=0.76cm \end{gathered}$$.

Here, $n_1$and $n_2$is the refractive index of the first and second medium respectively,$f$is the focal length and$R$is the radius of curvature.