Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

The cornea, a boundary between the air and the aqueous humor, has a 3.0cmfocal length when acting alone. What is its radius of curvature?

Short Answer

Expert verified

The radius of curvature isR=0.76cm

Step by step solution

Achieve better grades quicker with Premium

  • Unlimited AI interaction
  • Study offline
  • Say goodbye to ads
  • Export flashcards

Over 22 million students worldwide already upgrade their learning with Vaia!

01

Given Information.

We have given that:

The focal length is3.0cm.

We need find out the radius of curvature.

02

Simplify 

By using formula:

n1s+n2s'=(n1-n2)R

From previous formula, Let us find R:

1+n2f=n2-n1RR=fn2-n1n2R=3.0×1.34-1.001.34R=3.0×0.341.34R=3.0×0.253R=0.76cm.

Here, n1and n2is the refractive index of the first and second medium respectively,fis the focal length andRis the radius of curvature.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The resolution of a digital camera is limited by two factors:

diffraction by the lens, a limit of any optical system, and the fact

that the sensor is divided into discrete pixels. Consider a typical

point-and-shoot camera that has a 20-mm-focal-length lens and

a sensor with 2.5@mm@wide pixels.

a. First,ass ume an ideal, diffractionless lens. At a distance of

100 m, what is the smallest distance, in cm, between two

point sources of light that the camera can barely resolve? In

answering this question, consider what has to happen on the

sensor to show two image points rather than one. You can use

s′ = f because s W f.

b. You can achieve the pixel-limited resolution of part a only if

the diffraction width of each image point is no greater than

1 pixel in diameter. For what lens diameter is the minimum

spot size equal to the width of a pixel? Use 600 nm for the

wavelength of light.

c. What is the f-number of the lens for the diameter you found in

part b? Your answer is a quite realistic value of the f-number

at which a camera transitions from being pixel limited to

being diffraction limited. For f-numbers smaller than this

(larger-diameter apertures), the resolution is limited by the

pixel size and does not change as you change the aperture. For

f-numbers larger than this (smaller-diameter apertures), the

resolution is limited by diffraction, and it gets worse as you

“stop down” to smaller apertures

Yang can focus on objects 150cm away with a relaxed eye. With full accommodation, she can focus on objects 20cmaway. After her eyesight is corrected for distance vision, what will her near point be while wearing her glasses?

Mars (6800kmdiameter)is viewed through a telescope on a night when it is 1.1×108kmfrom the earth. Its angular size as seen through the eyepiece is 0.50°, the same size as the full moon seen by the naked eye. If the eyepiece focal length is 25mm, how long is the telescope?

Two light bulbs are 1.0mapart. from, what distance can these light bulbs be marginally resolved by a small telescope with a 4.0-cm-diameterobjective lens? assume that the lens is diffraction limited andλ=600nm.

Your task in physics laboratory is to make a microscope from two lenses. one lens has a focal length of 2.0cm,the other objective, and you want the eyepiece to be 16cmfrom the objective.

(a). For viewing with a relaxed eye, how far should the sample be from the objective lens?

(b). What is the magnification of your microscope?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free