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What is the f-number of a relaxed eye with the pupil fully dilated to 8.0mm? model the eye as a single lens 2.4 cm in front of the retina

Short Answer

Expert verified

The potential difference is11.4v.

Step by step solution

01

Given information 

Let the electrons accelerate from the pointto the rest of the pointwhere it reaches the speedof m/s. The conversation of energy says

02

Step 2. Explanation

Step 2: Explanation

This yield is

The potential difference is related to the potential energy difference throughelectrons

which yield is

03

Step 3. Substitution

By substituting the equation,k

We have to find

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Most popular questions from this chapter

A scientist needs to focus a helium-neon laser beam (ฮป=633nm)to a 10-ฮผm-diameterspot 8.0cmbehind a lens

(a) what focal-length lens should she use?

(b) what minimum diameter must the lens have?

Once dark adapted, the pupil of your eye is approximately 7 mm in diameter. The headlights of an oncoming car are 120 cm apart. If the lens of your eye is diffraction limited, at what distance are the two headlights marginally resolved? Assume a wavelength of 600 nm and that the index of refraction inside the eye is 1.33. (Your eye is not really good enough to resolve headlights at this distance, due both to aberrations in the lens and to the size of the receptors in your retina, but it comes reasonably close.)

In figure p35.26, parallel rays from the left are focused to a point at two locations on the optical axis. find the position of each location, giving your answer as a distance left or right of the lens.

FIGURE CP35.50shows a simple zoom lens in which the magnitudes of both focal lengths are f. If the spacing d<f, the image of the converging lens falls on the right side of the diverging lens. Our procedure of letting the image of the first lens act as the object of the second lens will continue to work in this case if we use a negative object distance for the second lens. This is called a virtual object. Consider an object very far to the left (sโ‰ˆโˆž)of the converging lens. Define the effective focal length as the distance from the midpoint between the lenses to the final image.

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Youโ€™ve been asked to build a telescope from a 2.0xmagnifying lens and a 5.0xmagnifying lens.

a. What is the maximum magnification you can achieve?

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