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The lens shown in FIGURE CP35.49 is called an achromatic doublet, meaning that it has no chromatic aberration. The left side is flat, and all other surfaces have radii of curvature R.

a. For parallel light rays coming from the left, show that the effective focal length of this two-lens system is f=R/12n2-n1-12, where localid="1648757054673" n1and n2are, respectively, the indices of refraction of the diverging and the converging lenses. Don’t forget to make the thin-lens approximation.

b. Because of dispersion, either lens alone would focus red rays and blue rays at different points. Define n1 and n2 as nblue-nred for the two lenses. What value of the ratio n1/n2makes fblue=fredfor the two-lens system? That is, the two-lens system does not exhibit chromatic aberration.

c. Indices of refraction for two types of glass are given in the table. To make an achromatic doublet, which glass should you use for the converging lens and which for the diverging lens? Explain

nblue nred

Crown glass 1.525 1.517

Flint glass 1.632 1.616

d. What value of R gives a focal length of 10.0cm?

Short Answer

Expert verified

a. The statement is proved below.

b. The value of the ration1n2is2.

c. The required statement is explained below.

d. The value of Ris 4.18cm.

Step by step solution

01

Part (a) Step 1 : Given Information

We have to find out effective focal length of the two lens.

02

Part (a) Step 2 : Calculation

n1s+n2s'=n2-n1Rn1+n2s'=n2-n1Rs'=Rn2n2-n1n2Rn2n2-n1+nair-f=nair-n2Rn2-n1R+1-f=1-n2R1-f=1-n2-n2+n1Rf=R2n2-n1-1

Here,fis focal length, nis refractive index andRis radius of curvature of lens


03

Part (b) Step 1 : Given Information

we have to find what value of the ration1/n2makesfblue=fred.

04

Part (b) Step 2 : Simplify

fblue=R2(n2)blue-(n1)blue-1andfred=R2(n2)red-(n1)red-1Now,fblue=fredwegetratio:fblue=fredR2(n2)blue-(n1)blue-1=R2(n2)red-(n1)red-12(n2)blue-(n1)blue-1=2(n2)red-(n1)red-12(n2)blue-(n1)red=(n1)blue-(n1)redn2=12n1

Here,fblueis focal length of blue andnis refractive index.

05

Part (c) Step 1 : Given Information

We have to find thenfor each type of glass.

06

Part (c) Step 2 : Simplification 

ncrown=1525-1517ncrown=0.008nflint=1.632-1.616nflint=0.016.

Here,nis the refractive index for respective names.

07

Part (d) Step 1 : Given Information

We have to find focal length in expression for R.

08

Part (d) Step 2 : Explanation

n1=1.632n2=1.525f=10cmSo,R=f(2n2-n1-1)R=(10.0cm)2(1.525)-1.632-1R=4.18cm.

Here, nis refractive index andfis the focal length of lens.

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Most popular questions from this chapter

A diffraction-limited lens can focus light to a 10μmdiameter spot on a screen. Do the following actions make the spot diameter larger, make it smaller, or leave it unchanged?

A. Decreasing the wavelength of the light.

B. Decreasing the lens diameter.

C. Decreasing the lens focal length.

D. Decreasing the lens-to-screen distance.

The resolution of a digital camera is limited by two factors:

diffraction by the lens, a limit of any optical system, and the fact

that the sensor is divided into discrete pixels. Consider a typical

point-and-shoot camera that has a 20-mm-focal-length lens and

a sensor with 2.5@mm@wide pixels.

a. First,ass ume an ideal, diffractionless lens. At a distance of

100 m, what is the smallest distance, in cm, between two

point sources of light that the camera can barely resolve? In

answering this question, consider what has to happen on the

sensor to show two image points rather than one. You can use

s′ = f because s W f.

b. You can achieve the pixel-limited resolution of part a only if

the diffraction width of each image point is no greater than

1 pixel in diameter. For what lens diameter is the minimum

spot size equal to the width of a pixel? Use 600 nm for the

wavelength of light.

c. What is the f-number of the lens for the diameter you found in

part b? Your answer is a quite realistic value of the f-number

at which a camera transitions from being pixel limited to

being diffraction limited. For f-numbers smaller than this

(larger-diameter apertures), the resolution is limited by the

pixel size and does not change as you change the aperture. For

f-numbers larger than this (smaller-diameter apertures), the

resolution is limited by diffraction, and it gets worse as you

“stop down” to smaller apertures

What is the aperture diameter of a 12mmfocal-length lens set to f/4.0?

Two converging lenses with focal lengths of 40 cm and 20 cm are 10 cm apart. A 2.0-cm-tall object is 15 cm in front of the 40-cm-focal-length lens. a). Use ray tracing to find the position and height of the image. Do this accurately using a ruler or paper with a grid, then make measurements on your diagram.

b). Calculate the image position and height. Compare with your ray-tracing answers in part a.

A microscope with a tube length of 180mmachieves a total magnification of 800Xwith a 40Xobjectives and a 20Xeye piece. The microscope is focused for viewing with a related eye. how far is the sample from the objective lens?

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