Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

The lens shown in FIGURE CP35.49 is called an achromatic doublet, meaning that it has no chromatic aberration. The left side is flat, and all other surfaces have radii of curvature R.

a. For parallel light rays coming from the left, show that the effective focal length of this two-lens system is f=R/12n2-n1-12, where localid="1648757054673" n1and n2are, respectively, the indices of refraction of the diverging and the converging lenses. Don’t forget to make the thin-lens approximation.

b. Because of dispersion, either lens alone would focus red rays and blue rays at different points. Define n1 and n2 as nblue-nred for the two lenses. What value of the ratio n1/n2makes fblue=fredfor the two-lens system? That is, the two-lens system does not exhibit chromatic aberration.

c. Indices of refraction for two types of glass are given in the table. To make an achromatic doublet, which glass should you use for the converging lens and which for the diverging lens? Explain

nblue nred

Crown glass 1.525 1.517

Flint glass 1.632 1.616

d. What value of R gives a focal length of 10.0cm?

Short Answer

Expert verified

a. The statement is proved below.

b. The value of the ration1n2is2.

c. The required statement is explained below.

d. The value of Ris 4.18cm.

Step by step solution

01

Part (a) Step 1 : Given Information

We have to find out effective focal length of the two lens.

02

Part (a) Step 2 : Calculation

n1s+n2s'=n2-n1Rn1+n2s'=n2-n1Rs'=Rn2n2-n1n2Rn2n2-n1+nair-f=nair-n2Rn2-n1R+1-f=1-n2R1-f=1-n2-n2+n1Rf=R2n2-n1-1

Here,fis focal length, nis refractive index andRis radius of curvature of lens


03

Part (b) Step 1 : Given Information

we have to find what value of the ration1/n2makesfblue=fred.

04

Part (b) Step 2 : Simplify

fblue=R2(n2)blue-(n1)blue-1andfred=R2(n2)red-(n1)red-1Now,fblue=fredwegetratio:fblue=fredR2(n2)blue-(n1)blue-1=R2(n2)red-(n1)red-12(n2)blue-(n1)blue-1=2(n2)red-(n1)red-12(n2)blue-(n1)red=(n1)blue-(n1)redn2=12n1

Here,fblueis focal length of blue andnis refractive index.

05

Part (c) Step 1 : Given Information

We have to find thenfor each type of glass.

06

Part (c) Step 2 : Simplification 

ncrown=1525-1517ncrown=0.008nflint=1.632-1.616nflint=0.016.

Here,nis the refractive index for respective names.

07

Part (d) Step 1 : Given Information

We have to find focal length in expression for R.

08

Part (d) Step 2 : Explanation

n1=1.632n2=1.525f=10cmSo,R=f(2n2-n1-1)R=(10.0cm)2(1.525)-1.632-1R=4.18cm.

Here, nis refractive index andfis the focal length of lens.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Infrared telescope, which use special infrared dictators, are able to do peer farther into star-forming regions of the galaxy because infrared light is not scattered as strongly as is visible light by the tenuous clouds of hydrogen gas from which new stars are created. for what wavelength of light is the scattering only 1%that of light with visible wavelength of 500nm?

A standardized biological microscope has an 8.0mmfocal length objective. what focal-length eyepiece should be used to achieve a total magnification of100x?

Two light bulbs are 1.0mapart. from, what distance can these light bulbs be marginally resolved by a small telescope with a 4.0-cm-diameterobjective lens? assume that the lens is diffraction limited andλ=600nm.

The Hubble Space Telescope has a mirror diameter of 2.4 m. Suppose the telescope is used to photograph stars near the center of our galaxy, 30,000 light years away, using red light with a wavelength of 650 nm.

a. What’s the distance (in km) between two stars that are marginally resolved? The resolution of a reflecting telescope is calculated exactly the same as for a refracting telescope.

b. For comparison, what is this distance as a multiple of the distance of Jupiter from the sun?

Two converging lenses with focal lengths of 40cmand 20cmare 10cmapart. A 2.0cmtall object is 15cmin front of the40cmfocal-length lens.

a. Use ray tracing to find the position and height of the image. Do this accurately using a ruler or paper with a grid, then make measurements on your diagram.

b. Calculate the image position and height. Compare with your ray-tracing answers in part a.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free