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The lens shown in FIGURE CP35.49 is called an achromatic doublet, meaning that it has no chromatic aberration. The left side is flat, and all other surfaces have radii of curvature R.

a. For parallel light rays coming from the left, show that the effective focal length of this two-lens system is f=R/12n2-n1-12, where localid="1648757054673" n1and n2are, respectively, the indices of refraction of the diverging and the converging lenses. Don’t forget to make the thin-lens approximation.

b. Because of dispersion, either lens alone would focus red rays and blue rays at different points. Define n1 and n2 as nblue-nred for the two lenses. What value of the ratio n1/n2makes fblue=fredfor the two-lens system? That is, the two-lens system does not exhibit chromatic aberration.

c. Indices of refraction for two types of glass are given in the table. To make an achromatic doublet, which glass should you use for the converging lens and which for the diverging lens? Explain

nblue nred

Crown glass 1.525 1.517

Flint glass 1.632 1.616

d. What value of R gives a focal length of 10.0cm?

Short Answer

Expert verified

a. The statement is proved below.

b. The value of the ration1n2is2.

c. The required statement is explained below.

d. The value of Ris 4.18cm.

Step by step solution

01

Part (a) Step 1 : Given Information

We have to find out effective focal length of the two lens.

02

Part (a) Step 2 : Calculation

n1s+n2s'=n2-n1Rn1+n2s'=n2-n1Rs'=Rn2n2-n1n2Rn2n2-n1+nair-f=nair-n2Rn2-n1R+1-f=1-n2R1-f=1-n2-n2+n1Rf=R2n2-n1-1

Here,fis focal length, nis refractive index andRis radius of curvature of lens


03

Part (b) Step 1 : Given Information

we have to find what value of the ration1/n2makesfblue=fred.

04

Part (b) Step 2 : Simplify

fblue=R2(n2)blue-(n1)blue-1andfred=R2(n2)red-(n1)red-1Now,fblue=fredwegetratio:fblue=fredR2(n2)blue-(n1)blue-1=R2(n2)red-(n1)red-12(n2)blue-(n1)blue-1=2(n2)red-(n1)red-12(n2)blue-(n1)red=(n1)blue-(n1)redn2=12n1

Here,fblueis focal length of blue andnis refractive index.

05

Part (c) Step 1 : Given Information

We have to find thenfor each type of glass.

06

Part (c) Step 2 : Simplification 

ncrown=1525-1517ncrown=0.008nflint=1.632-1.616nflint=0.016.

Here,nis the refractive index for respective names.

07

Part (d) Step 1 : Given Information

We have to find focal length in expression for R.

08

Part (d) Step 2 : Explanation

n1=1.632n2=1.525f=10cmSo,R=f(2n2-n1-1)R=(10.0cm)2(1.525)-1.632-1R=4.18cm.

Here, nis refractive index andfis the focal length of lens.

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Most popular questions from this chapter

The center of the galaxy is filled with low-density hydrogen gas that scatters light rays. An astronomer wants to take a picture of the center of the galaxy. Will the view be better using ultraviolet light, visible light, or infrared light? Explain.

Two converging lenses with focal lengths of 40 cm and 20 cm are 10 cm apart. A 2.0-cm-tall object is 15 cm in front of the 40-cm-focal-length lens. a). Use ray tracing to find the position and height of the image. Do this accurately using a ruler or paper with a grid, then make measurements on your diagram.

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A 2.0-cm-tall object is 20cmto the left of a lens with a focal length of10cmA second lens with a focal length of 15cmis30cmto the right of the first lens.

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