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The radium isotope R223a, an alpha emitter, has a half-life of localid="1650483334573" 11.43days. You happen to have a localid="1650483350108" 1.0gcube of R223a, so you decide to use it to boil water for tea. You fill a well-insulated container with 100mLof water at 18°Cand drop in the cube of radium. How long will it take the water to boil?

Short Answer

Expert verified

Time taken to boil water is,t=18.9s

Step by step solution

01

Given information

We are given that,

Half life is, t12=11.43days=9.876×105s

And m=100mL=0.10L

AndR223aR219n+H4e

02

Explanation

Energy is,

E=mR223a-mR219n-mH4e×931.49MeV/u=223.018499u-219.009477u-4.002602×931.49MeV/u=5.98MeV

Energy needed to raise temperature of water at 18°Cto100°C

localid="1650483848390" Q=mct=0.101kg1L4190J/kgK100K-18K=34400J

Now, value of α-particleis,

localid="1650483872050" 5.98×106eV×1.6×10-19J/eV=9.57×10-13J

No. of decays,

localid="1650483894424" N=Qα-particle=34400J9.57×10-13J=3.59×1016

03

Simplify

No. of radium atoms is,

N0=1g223g/mol×6.02×1023atoms/mol=2.7×1021atoms

Now, tis given as,

localid="1650483972186" dNdt=Nt=-rN0t=-NrN0=-τNN0=t12ln2×NN0=9.876×105sln2×-3.59×10162.7×1021=18.9s

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