Question

Use the potential-energy diagram in Figure$42.8$to estimate the strength of the strong force between two nucleons separated by $1.5fm$.

Short answer

The strong force between the two nucleons separated by $1.5fm$is$6.393\times {10}^{-19}N$

Step-by-step solution

Given information.

We have been given that,

Two nucleons which are separated by $1.5fm$

We need to find the strong force acting between them.

Simplify.

From the graph ,it clearly states that the maximum force occurs when distance between them is $1.5fm$.

Therefore,

The formula for force = $\frac{{\rm K}Z{e}^2}{r^2}N$

$\left(e=chargeofproton,r=dis\tan cebetweenthem,Z=1\right)$

$$\begin{gathered} =\frac{8.98\times 1\times 1.602\times {10}^{-19}}{{(1.5\times {10}^{-19})}^2}N \\ =6.393\times {10}^{-19}N \end{gathered}$$ $\left({\rm K}=8.98\right)$

This is highly attractive in nature.