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Chapter 7: Q. 2 (page 176)

How does a sprinter sprint? What is the forward force on a sprinter as she accelerates? Where does that force come from? Your explanation should include an interaction diagram and a free-body diagram.

Short Answer

Expert verified

The interaction diagram and free body diagram is given below.
The system consist of both weight lifter and the bar bell together.

Step by step solution

01

Step 1:Weightfilter

The preceding are the initiative couples of just a weightlifter making a stand out of a seated position with a massive hammer atop his neck.

02

Interaction Diagram

03

Forward Forces

$B B =$ barbell

$W_{L} =$ weight of the lifter

role="math" localid="1651387074662" $n_{S =}$ normal force

$E =$ Earth

$F_{B B =}$ force of the barbell

04

Free-body diagram

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Most popular questions from this chapter

The $2000 k g$ cable car shown in FIGURE P $7.42$ descends a $200$ -m-high hill. In addition to its brakes, the cable car controls its speed by pulling an $1800 k g$ counterweight up the other side of the hill. The rolling friction of both the cable car and the counterweight are negligible.

a. How much braking force does the cable car need to descend at constant speed?

b. One day the brakes fail just as the cable car leaves the top on its downward journey. What is the runaway car’s speed at the bottom of the hill?

The $1.0 k g$ block in FIGURE EX $7.24$ is tied to the wall with a rope. It sits on top of the $2.0 k g$ block. The lower block is pulled to the right with a tension force of $20 N$ . The coefficient of kinetic friction at both the lower and upper surfaces of the $2.0 k g$ block is $μ_{k} = 0.40$

a. What is the tension in the rope attached to the wall?

b. What is the acceleration of the $2.0 k g$ block?

A rocket burns fuel at a rate of $5.0 k g / s$ , expelling the exhaust gases at a speed of $4.0 k m / s$ relative to the rocket. We would like to find the thrust of the rocket engine.

a. Model the fuel burning as a steady ejection of small pellets, each with the small mass $∆ m$ . Suppose it takes a short time $∆ t$ to accelerate a pellet (at constant acceleration) to the exhaust speed $v_{e x}$ . Further, suppose the rocket is clamped down so that it can’t recoil. Find an expression for the magnitude of the force that one pellet exerts on the rocket during the short time while the pellet is being expelled.

b. If the rocket is moving, $v_{e x}$ is no longer the pellet’s speed through space but it is still the pellet’s speed relative to the rocket. By considering the limiting case of $∆ m$ and $∆ t$ approaching zero, in which case the rocket is now burning fuel continuously, calculate the rocket thrust for the values given above.

Will hanging a magnet in front of the iron cart in the given figure make it go? Explain.

Teams red and blue are having a tug-of-war. According to Newton’s third law, the force with which the red team pulls on the blue team exactly equals the force with which the blue team pulls on the red team. How can one team ever win? Explain

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