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25. II FIGURE EX4.25 shows the angular-velocity-versus-time graph for a particle moving in a circle, starting from ฮธ0=0โ€Šโ€Šradat t=0s. Draw the angular-position-versus-time graph. Include an appropriate scale on both axes.

Short Answer

Expert verified

The angular-position-versus-time graph is

Step by step solution

01

Step 1.  The displacement between time 0 s to 4s 

In the given time from 0 s to 4s, the angular velocity of the particle is20rad/s

The angular position of the particle is

ฮ”ฮธ1=ฯ‰1โ€Šฮ”t1ฮ”ฮธ1=(20rad/s)(4sโˆ’0s)ฮ”ฮธ1=80rad

The angular velocity of the particle is constant but time is changing so the angular position of the particle will increase from0โ€Šโ€Šโ€Šrad to80โ€Šโ€Šโ€Šrad linearly.

02

Step 2.  The displacement between time 4s to 8s 

For 4s to 8s, the angular velocity of the particle is0โ€Šโ€Šโ€Šrad/s

The angular position of the particle is

ฮ”ฮธ2=ฯ‰2ฮ”t2ฮ”ฮธ2=(0rad/s)(6sโˆ’4s)=0rad

The angular velocity of the particle is zero, so the angular position of the particle will remain same at the initial position of 80โ€Šโ€Šโ€Šradโ€Š. So the angular position is linear flat.

03

Step 3.  The displacement between time 8s to 10s 

From 6s to 8s , the angular velocity of the particle is โˆ’10rad/s

ฮ”ฮธ3=ฯ‰3ฮ”t3ฮ”ฮธ3=(โˆ’10rad/s)(8sโˆ’6s)ฮ”ฮธ3=โˆ’20rad

The angular velocity of the particle is constant but time is changing so the angular position of the particle will decrease from 80 rad to 60 rad linearly in time form 8 s to 6 s.

04

Step 4. The graph of angular position

The following graph shows the graph of angular position versus time for a particle moving in circular path.

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