Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Ann and Carol are driving their cars along the same straight road. Carol is located at x = 2.4 mi at t = 0 h and drives at a steady 36 mph. Ann, who is traveling in the same direction, is located at x = 0.0 mi at t = 0.50 h and drives at a steady 50 mph.

a. At what time does Ann overtake Carol?

b. What is their position at this instant?

c. Draw a position-versus-time graph showing the motion of both Ann and Carol.

Short Answer

Expert verified

Ann's car would cross Carol's car after 2 hours at a distance of 74.4 m

Step by step solution

01

Step 1. Write the given information

Let the initial point of Carol is Y

The velocity of Carol is vic=36.0m/h

The position of Carol is role="math" localid="1648444538537" xic=2.4m

The time at this instant is role="math" localid="1648444715128" tic=0h

Similarly,
The initial point of Ann is X

The velocity of Ann is viA=50m/h

The position of Ann is xiA=0m
The time at this instant is tiA=0.5h

02

Step 2. (a) To determine the time at which Ann will cross Carol

Let the point of crossing is Z. At this point let the time is t
The position of Carol at this point is xfc

The position of Ann at this point is xfA

Write the equation of motion at point Z for Carol

xfc=xic+vict-tic
Insert the known variables in the above expression,

localid="1648445871907" xfc=2.4+36t-0xfc=2.4+36t......(1)

Similarly, write the equation of motion for Ann at point Z

xfA=xiA+viAt-tiAxfA=0+50t-0.5xfA=50t-25.......(2)

Compare the equations (1) and (2)
2.4+36t=50t-2527.4=14tt=2h
Thus, after 2 hours, Ann's car would cross Carol's car.

03

Step3. (b) To determine the position of crossing

The position of crossing is determined by substituting the value of tin equation (1 ) or (2),

Consider equation (1)

xfc=2.4+36(2)xfc=74.4m
Thus, Ann's car would cross Caol's car at 74.4 m.

04

To draw the position-time graph of Carol and Ann

The position-time graph of Carol and Ann's car is shown below. The red line shows the change in position of Carol's car and the blue line shows the change in position of Ann's Car. They both meet at the time of 2 hours at a distance of 74.4 meters.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A very slippery block of ice slides down a smooth ramp tilted at angle u. The ice is released from rest at vertical height h above the bottom of the ramp. Find an expression for the speed of the ice at the bottom

One game at the amusement park has you push a puck up a long, frictionless ramp. You win a stuffed animal if the puck, at its highest point, comes to within 10 cm of the end of the ramp without going off. You give the puck a push, releasing it with a speed of 5.0 m/s when it is 8.5 m from the end of the ramp. The puckโ€™s speed after traveling 3.0 m is 4.0 m/s. How far is it from the end when it stops?

FIGURE EX2.7 showed the velocity graph of blood in the aorta. What is the bloodโ€™s acceleration during each phase of the motion, speeding up and slowing down?

Careful measurements have been made of Olympic sprinters

in the 100 meter dash. A quite realistic model is that the sprinterโ€™s

velocity is given by

vx=a(1-e-bt)

where t is in s, vx is in m/s, and the constants a and b are characteristic

of the sprinter. Sprinter Carl Lewisโ€™s run at the 1987

World Championships is modeled with a = 11.81 m/s and

b = 0.6887 s-1.

a. What was Lewisโ€™s acceleration at t = 0 s, 2.00 s, and 4.00 s?

b. Find an expression for the distance traveled at time t.

c. Your expression from part b is a transcendental equation,

meaning that you canโ€™t solve it for t. However, itโ€™s not hard to

use trial and error to find the time needed to travel a specific

distance. To the nearest 0.01 s, find the time Lewis needed to

sprint 100.0 m. His official time was 0.01 s more than your

answer, showing that this model is very good, but not perfect.

Bob is driving the getaway car after the big bank robbery. Heโ€™s going 50 m/s when his headlights suddenly reveal a nail strip that the cops have placed across the road 150 m in front of him. If Bob can stop in time, he can throw the car into reverse and escape. But if he crosses the nail strip, all his tires will go flat and he will be caught. Bobโ€™s reaction time before he can hit the brakes is 0.60 s, and his carโ€™s maximum deceleration is 10 m/s2. Does Bob stop before or after the nail strip? By what distance?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free