Question

A very slippery ice cube slides in a vertical plane around the inside of a smooth, $20-cm$-diameter horizontal pipe. The ice cube’s speed at the bottom of the circle is $3.0m/s$. What is the ice cube’s speed at the top?

Short answer

Ice cube's speed at the top will be zero.

Step-by-step solution

Speed : 

It is the change in an object's location with regard to time.

Explanation : 

A highly slippery ice cube moves vertically across the inside of a smooth horizontal pipe with a diameter of $20cm$. At the bottom of the circle, the ice cube's speed is $3.0m/s$.

Ice cube's total energy $KE+PE$remains constant $\frac{1}{2}m{v}^2+mgh=cons\tan t$,

$v$= ice cube's velocity,

$-h$= height from the bottom of the vertical circle.

The frictional force does no work since the pipe is smooth. When an ice cube is released from rest from a point on the vertical circle, it will reach the release height at the same speed as when it was released. As a result, the top ice cube's speed will be zero.