Question

$(600g)(4.0m/s)=(400g)(3.0m/s)+(200g){\left(v_{ix}\right)}_2$

a. Write a realistic problem for which this is the correct equation(s).

b. Finish the solution of the problem, including a pictorial representation.

Short answer

a) The realistic problem is "200g ball moving towards right collides with the ball of mass 400g moving with speed 3 m/s and then they moves together. Find the speed of 200g ball before colliding"

b) Solution for the problem is${\left(v_{i.x}\right)}_2=6m/s$

Step-by-step solution

Step 1. Given equation is :(600 g)(4.0 m/s)=(400 g)(3.0 m/s)+(200 g)vix2

We need to find out a realistic problem for which this is the correct equation and have to find out the solution including pictorial representation.

Step 2. Expressing the realistic problem of the given equation. 

There are two masses that stick together after the collision.

So the equation will be :

"200g ball moving towards right collides with the ball of mass 400g moving with speed 3 m/s and then they moves together. Find the speed of 200g ball before colliding"

Step 3. Using law of conservation of mass for solving the equation.

$$\begin{gathered} \left(600g\right)(4m/s)=\left(400g\right)(3m/s)+\left(200g\right){\left(v_{ix}\right)}_2 \\ {\left(v_{ix}\right)}_2=\frac{\left(600g\right)(4m/s)-\left(400g\right)(3m/s)}{200g} \\ {\left(v_{ix}\right)}_2=6m/s \end{gathered}$$

Pictorial Representation,