Question

A particle of mass m is at rest at t = 0. Its momentum for $t>0$ is given by $p_x=6t^2$ kg m/s, where t is in s. Find an expression for$F_x\left(t\right)$ , the force exerted on the particle as a function of time.

Short answer

The expression for the force is$F_x\left(t\right)=12t$

Step-by-step solution

Step 1. Given information

Equation of momentum is$p\left(t\right)=6t^2$

Step 2. Evaluating force equation

As we know, $F=\frac{dp}{dt}$

So,$F_x\left(t\right)=\frac{d}{dt}\left(6t^2\right)=12t$