Question

A $200g$ball is dropped from a height of $2.0m$, bounces on a hard floor, and rebounds to a height of $1.5m$. FIGURE P11.41 shows the impulse received from the floor. What maximum force does the floor exert on the ball?

Short answer

The maximum force exerted on the ball is$7.5\times {10}^{-10}Ns$

Step-by-step solution

Step 1. Given information

We need to find how much maximum force does the floor exert on the ball.

Step 2. Calculation

To find the average force used to eject pollen grain we use newton's second law $F_{average}=ma=(1\times {10}^{-10}kg)\times (2.5\times {10}^4)m/s^2=2.5\times {10}^{-6}N$

The impulse can be find from average force acting on pollen grains

$J=F_{average}△t=(2.5\times {10}^{-6}N)\times (0.3\times {10}^{-3})s=7.5\times {10}^{-10}Ns$